Sunil Mohan Adapa f65b4ec407
views: Don't require sending diagnostics module name separately
- Reuse the app_id already available to the view.

- Implement automatically detecting if an app has implemented diagnostics.

Signed-off-by: Sunil Mohan Adapa <sunil@medhas.org>
Reviewed-by: James Valleroy <jvalleroy@mailbox.org>
2019-12-30 11:38:02 -05:00

53 lines
1.8 KiB
Python

#
# This file is part of FreedomBox.
#
# This program is free software: you can redistribute it and/or modify
# it under the terms of the GNU Affero General Public License as
# published by the Free Software Foundation, either version 3 of the
# License, or (at your option) any later version.
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU Affero General Public License for more details.
#
# You should have received a copy of the GNU Affero General Public License
# along with this program. If not, see <http://www.gnu.org/licenses/>.
#
from django.contrib import messages
from django.utils.translation import ugettext_lazy as _
from plinth import actions
from plinth.modules.mumble import (clients, description, icon_filename,
manual_page, name, port_forwarding_info)
from plinth.modules.mumble.forms import MumbleForm
from plinth.views import AppView
class MumbleAppView(AppView):
app_id = 'mumble'
name = name
description = description
clients = clients
manual_page = manual_page
port_forwarding_info = port_forwarding_info
icon_filename = icon_filename
form_class = MumbleForm
def form_valid(self, form):
"""Apply new superuser password if it exists"""
new_config = form.cleaned_data
password = new_config.get('super_user_password')
if password:
actions.run_as_user(
'mumble',
['create-password'],
input=password.encode(),
become_user="mumble-server",
)
messages.success(self.request,
_('SuperUser password successfully updated.'))
return super().form_valid(form)